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The sketch below shows cross-section of ...

The sketch below shows cross-section of the equipotential surface between two charged conductors that are shown im solid black. Some points on the equipotential surface near the conductors are marked as A , B , C.........The arrangement lines in the air.(Take `epsilon_0= 8.85xx 10^(-12) C^(2) N^(-1)m^(-2)` ) The surface charge density of the plate is equal to

A

`8.85xx10^(-10) C//m^(2)`

B

`-8.85xx10^(-10) C//m^(2)`

C

`17.7xx10^(-10) C//m^(2)`

D

`-17.7xx10^(-10) C//m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`E=(-dV)/(dr), sigma/in_(0)=(-30)/0.3`
`sigma=8.85xx10^(-12)xx10^(2)=8.85xx10^(-10) C//m^(2)`
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