The `pK_(a)` for acid A is greater than `pK_(a)` for acid B, the strong
acid is :-

Options

A. B
B. A
C. Both Aand B
D. None of these

Explanation

To determine which acid is stronger based on their pKa values, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Relationship Between pKa and Ka**:
- The pKa of an acid is defined as \( pK_a = -\log(K_a) \), where \( K_a \) is the acid dissociation constant.
- A lower pKa value indicates a higher \( K_a \), meaning the acid dissociates more completely in solution.

2. **Compare the Given pKa Values**:
- We are given that \( pK_a \) for acid A is greater than \( pK_a \) for acid B. This can be expressed as:
\[ pK_a(A) > pK_a(B) \]

3. **Interpret the Comparison**:
- Since \( pK_a(A) \) is greater than \( pK_a(B) \), it implies that:
\[ K_a(A) < K_a(B) \]
- This means that acid A has a lower tendency to dissociate compared to acid B.

4. **Determine Which Acid is Stronger**:
- Since a stronger acid has a higher \( K_a \) and a lower pKa, and we have established that \( K_a(B) > K_a(A) \), we conclude that:
\[ \text{Acid B is the stronger acid.} \]

5. **Final Answer**:
- Therefore, the stronger acid is **B**.