The oxidation number of C in `K_(2)C_(2)O_(4)` is

Options

A. `+3`
B. `+4`
C. 0
D. `+1`

Answer

To find the oxidation number of carbon in \( K_2C_2O_4 \) (potassium oxalate), we can follow these steps:

### Step 1: Identify the oxidation states of known elements
In the compound \( K_2C_2O_4 \):
- Potassium (K) typically has an oxidation state of +1.
- Oxygen (O) typically has an oxidation state of -2.

### Step 2: Set up the equation based on the overall charge
Since \( K_2C_2O_4 \) is a neutral compound, the sum of the oxidation states must equal 0. Let the oxidation state of carbon (C) be \( x \).

The formula contains:
- 2 potassium atoms: \( 2 \times (+1) = +2 \)
- 4 oxygen atoms: \( 4 \times (-2) = -8 \)
- 2 carbon atoms: \( 2 \times x = 2x \)

### Step 3: Write the equation
Now, we can set up the equation:
\[ 2 + 2x - 8 = 0 \]

### Step 4: Solve for x
Rearranging the equation gives:
\[ 2x - 6 = 0 \]
\[ 2x = 6 \]
\[ x = 3 \]

### Step 5: Conclusion
Thus, the oxidation number of carbon in \( K_2C_2O_4 \) is +3.