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Which of the following molecule is plana...

Which of the following molecule is planar due to back bonding

A

`NCl_(3)`

B

`PF_(3)`

C

`BF_(3)`

D

None

Text Solution

AI Generated Solution

The correct Answer is:
To determine which molecule is planar due to back bonding, we need to analyze the options provided in the question. Here’s a step-by-step solution: ### Step 1: Understand Back Bonding Back bonding occurs when a ligand donates electron density to a metal or non-metal center that has empty orbitals. For effective back bonding, the following conditions must be met: - The central atom (metal or non-metal) must have empty orbitals. - The ligand must have lone pairs or filled p orbitals. - There should be good orbital overlap between the metal and the ligand. ### Step 2: Analyze Each Option We will analyze the options provided in the question to identify if they meet the criteria for back bonding. #### Option A: Nitrogen with 3 Chlorine atoms (NCl3) - Nitrogen has a lone pair and is connected to three chlorine atoms. - Chlorine has filled 3p orbitals, and nitrogen has filled 2p orbitals. - There are no empty d-orbitals in nitrogen. - The overlap between 2p (N) and 3p (Cl) is not effective. - **Conclusion**: Not planar due to back bonding. #### Option B: Phosphorus with 3 Fluorine atoms (PF3) - Phosphorus has a lone pair and is connected to three fluorine atoms. - Fluorine has filled 2p orbitals, and phosphorus has filled 3p orbitals. - There are no empty d-orbitals in phosphorus. - The overlap between 3p (P) and 2p (F) is not effective. - **Conclusion**: Not planar due to back bonding. #### Option C: Boron with 3 Fluorine atoms (BF3) - Boron has an empty p orbital (2p) and is connected to three fluorine atoms. - Fluorine has filled 2p orbitals. - The overlap between the empty 2p orbital of boron and the filled 2p orbitals of fluorine is excellent. - Back bonding occurs, leading to partial double bond character. - The geometry of BF3 is trigonal planar. - **Conclusion**: Planar due to back bonding. ### Step 3: Final Answer Based on the analysis, the molecule that is planar due to back bonding is **Option C: BF3**. ---
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