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Which ion would you expect to have the m...

Which ion would you expect to have the maximum splitting of - orbitals

A

`[Fe(CN)_(6)]^(-4)`

B

`[Fe(CN)_(6)]^(-3)`

C

`Fe(H_(2)O)_(6)]^(+2)`

D

`[Fe(H_(2)O)_(6)]^(+3)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which ion would have the maximum splitting of d-orbitals, we can follow these steps: ### Step 1: Understand d-Orbital Splitting In an octahedral complex, the five d-orbitals split into two energy levels: the lower-energy t2g orbitals and the higher-energy eg orbitals. The extent of this splitting depends on the nature of the ligands surrounding the metal ion and the number of d-electrons in the metal. **Hint:** Remember that the splitting of d-orbitals occurs due to the electrostatic interactions between the ligands and the d-electrons of the metal ion. ### Step 2: Identify the Ligands The strength of the ligand plays a crucial role in the degree of splitting. Strong field ligands (like CN⁻) cause greater splitting compared to weak field ligands (like H2O). **Hint:** Strong field ligands lead to larger splitting (greater Δo), while weak field ligands lead to smaller splitting. ### Step 3: Analyze the Given Options We need to analyze the oxidation states and electronic configurations of the metal ions in the given complexes. The options typically include different metal ions and ligands. **Hint:** Calculate the oxidation state of the metal in each complex to determine how many d-electrons are present. ### Step 4: Calculate the d-Electron Count For each metal ion, determine the number of d-electrons based on its oxidation state. The more d-electrons present, the lesser the splitting energy, as more electrons lead to increased electron-electron repulsion. **Hint:** Use the electronic configuration of the metal to find the number of d-electrons after accounting for the oxidation state. ### Step 5: Compare the Splitting Once you have the d-electron counts for the metal ions in the complexes with strong field ligands, compare them. The complex with the fewer d-electrons will experience greater splitting. **Hint:** Remember that a lower number of d-electrons in the presence of a strong field ligand leads to maximum splitting of d-orbitals. ### Step 6: Conclusion After analyzing the options, you will find that the ion with the maximum splitting of d-orbitals is the one with the strong field ligand and the least number of d-electrons. **Final Answer:** The ion expected to have the maximum splitting of d-orbitals is the one with a strong field ligand and fewer d-electrons, which in this case is option number 2.
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Knowledge Check

  • Among NH_(3),H_(2)O , and HF , which would you expect to have highest magnitude of hydrogen bonding and why?

    A
    HF due to maximum polarity.
    B
    `H_(2)O` due to lone pairs of electrons.
    C
    `NH_(3)` due to small size of nitrogen.
    D
    `H_(2)S` due to higher electron affinity of sulphur.
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