Which of the following compound will give curdy precipiate with `AgNO_(3)` solution:

Options

A.
B.
C.
D.

Answer

To determine which compound will give a curdy precipitate with AgNO₃ solution, we need to identify which of the given compounds can release chloride ions (Cl⁻) when reacted with silver nitrate (AgNO₃). The formation of a curdy precipitate indicates the formation of silver chloride (AgCl), which is a white precipitate.

### Step-by-Step Solution:

1. **Understanding the Reaction**:
- Silver nitrate (AgNO₃) reacts with chloride ions (Cl⁻) to form silver chloride (AgCl), which is a curdy precipitate.
- The reaction can be represented as:
\[ \text{AgNO}_3 + \text{Cl}^- \rightarrow \text{AgCl} \downarrow + \text{NO}_3^- \]

2. **Analyzing the Options**:
- We need to assess each compound to see if it can release a chloride ion when reacted with AgNO₃.

3. **Option 1: Chlorobenzene (C₆H₅Cl)**:
- Chlorobenzene has a chlorine atom attached to a benzene ring. The chlorine is part of a stable aromatic system and is not easily removed.
- **Conclusion**: Chlorobenzene will not give a curdy precipitate.

4. **Option 2: Vinyl Chloride (CH₂=CHCl)**:
- Vinyl chloride can potentially release a chloride ion, but upon losing Cl⁻, it forms a carbocation (CH₂=CH⁺), which is unstable.
- **Conclusion**: Vinyl chloride will not give a curdy precipitate.

5. **Option 3: Cyclohexene with Chlorine (C₆H₈Cl)**:
- This compound can also release a chloride ion, but the resulting structure after losing Cl⁻ will have a positive charge on a double bond, which is also unstable.
- **Conclusion**: This compound will not give a curdy precipitate.

6. **Option 4: A Seven-Membered Ring with Chlorine**:
- This compound can release a chloride ion, and upon doing so, it forms a stable aromatic compound.
- **Conclusion**: This compound will give a curdy precipitate with AgNO₃.

### Final Answer:
The compound that will give a curdy precipitate with AgNO₃ solution is **Option 4** (the seven-membered ring with chlorine).