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The fricition coefficient between the ta...

The fricition coefficient between the table and block shown in fig. is 0.2 find the acceleration of the system (Take `g=10 m//s^(2)`)

Text Solution

Verified by Experts

For three blocks the equations of motion are-
`a=(15g-5g-g)/(25)=((9g)/(25))`
`15g-T_(1)=15arArrT_(1)=15g-(135g)/(25)=(375g-135g)/(25)=96N`
`T_(2)-5g=5((9g)/(25))rArr T_(2)=5g+(9g)/(5)=(34g)/(5)=68N`
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