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125 ml of 8% w/v NaOH solution (sp. grav...

125 ml of 8% w/v NaOH solution (sp. gravity 1) is added to 125 ml of 10% w/v HCl solution. The nature of resultant solution would be ____

A

Acidic

B

Basic

C

Neutral

D

Can not be predicted

Text Solution

AI Generated Solution

The correct Answer is:
To determine the nature of the resultant solution when 125 ml of 8% w/v NaOH solution is mixed with 125 ml of 10% w/v HCl solution, we can follow these steps: ### Step 1: Calculate the mass of NaOH in the solution Given that the NaOH solution is 8% w/v, this means there are 8 grams of NaOH in 100 ml of solution. For 125 ml of NaOH solution: \[ \text{Mass of NaOH} = \left(\frac{8 \text{ g}}{100 \text{ ml}}\right) \times 125 \text{ ml} = 10 \text{ g} \] ### Step 2: Calculate the number of moles of NaOH The molar mass of NaOH is 40 g/mol. To find the number of moles of NaOH: \[ \text{Moles of NaOH} = \frac{\text{Mass of NaOH}}{\text{Molar mass of NaOH}} = \frac{10 \text{ g}}{40 \text{ g/mol}} = 0.25 \text{ moles} \] ### Step 3: Calculate the mass of HCl in the solution For the HCl solution, which is 10% w/v, this means there are 10 grams of HCl in 100 ml of solution. For 125 ml of HCl solution: \[ \text{Mass of HCl} = \left(\frac{10 \text{ g}}{100 \text{ ml}}\right) \times 125 \text{ ml} = 12.5 \text{ g} \] ### Step 4: Calculate the number of moles of HCl The molar mass of HCl is 36.5 g/mol. To find the number of moles of HCl: \[ \text{Moles of HCl} = \frac{\text{Mass of HCl}}{\text{Molar mass of HCl}} = \frac{12.5 \text{ g}}{36.5 \text{ g/mol}} \approx 0.342 \text{ moles} \] ### Step 5: Compare the moles of HCl and NaOH NaOH dissociates to give OH⁻ ions, and HCl dissociates to give H⁺ ions. The reaction can be represented as: \[ \text{NaOH} + \text{HCl} \rightarrow \text{NaCl} + \text{H}_2\text{O} \] From the calculations: - Moles of OH⁻ from NaOH = 0.25 moles - Moles of H⁺ from HCl = 0.342 moles ### Step 6: Determine the nature of the resultant solution Since the moles of H⁺ (0.342 moles) are greater than the moles of OH⁻ (0.25 moles), the solution will be acidic in nature. ### Final Answer: The nature of the resultant solution is **acidic**. ---
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