Oxidation of 2-methyl propane-1,2-diol with periodic acid gives:-

Options

A. Propionic acid and formaldehyde
B. Acetone and formaldehyde
C. Acetone and acetic acid
D. Acetone and propionic acid

Answer

To solve the question regarding the oxidation of 2-methylpropane-1,2-diol with periodic acid, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of 2-Methylpropane-1,2-diol**:
- The molecular formula for 2-methylpropane-1,2-diol is C5H12O2.
- The structure can be represented as:
```
CH3
|
CH3-CH-CH2-OH
|
OH
```
- In this structure, the first carbon (C1) has a hydroxyl (OH) group and is a primary alcohol, while the second carbon (C2) has a methyl group and is a tertiary alcohol.

2. **Understand the Oxidation Reaction**:
- Periodic acid (HIO4) is known to oxidize diols to carbonyl compounds.
- In this case, the primary alcohol (C1) will be oxidized to formaldehyde (HCHO), and the tertiary alcohol (C2) will be oxidized to acetone (CH3COCH3).

3. **Perform the Oxidation**:
- The oxidation of the primary alcohol (C1) leads to the formation of formaldehyde:
```
CH3-CH(OH)-CH2-OH → HCHO (formaldehyde)
```
- The oxidation of the tertiary alcohol (C2) leads to the formation of acetone:
```
CH3-CH(OH)-CH2-OH → CH3COCH3 (acetone)
```

4. **Summarize the Products**:
- After the oxidation of 2-methylpropane-1,2-diol with periodic acid, the products formed are:
- Acetone (CH3COCH3)
- Formaldehyde (HCHO)

5. **Final Answer**:
- Therefore, the oxidation of 2-methylpropane-1,2-diol with periodic acid gives acetone and formaldehyde.