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A vector perpendicular to (4hati-3hatj) ...

A vector perpendicular to `(4hati-3hatj)` may be :

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To find a vector that is perpendicular to the vector \( \vec{A} = 4\hat{i} - 3\hat{j} \), we can use the property that the dot product of two perpendicular vectors is zero. ### Step-by-Step Solution: 1. **Define the Perpendicular Vector**: Let the vector we are looking for be \( \vec{B} = x\hat{i} + y\hat{j} \). 2. **Set Up the Dot Product**: The dot product of \( \vec{A} \) and \( \vec{B} \) must equal zero for them to be perpendicular: \[ \vec{A} \cdot \vec{B} = (4\hat{i} - 3\hat{j}) \cdot (x\hat{i} + y\hat{j}) = 0 \] 3. **Calculate the Dot Product**: Using the properties of the dot product: \[ \vec{A} \cdot \vec{B} = 4x + (-3)y = 4x - 3y \] Set this equal to zero: \[ 4x - 3y = 0 \] 4. **Rearrange the Equation**: Rearranging gives: \[ 4x = 3y \quad \Rightarrow \quad \frac{x}{y} = \frac{3}{4} \] 5. **Find Values for x and y**: From the ratio \( \frac{x}{y} = \frac{3}{4} \), we can express \( x \) and \( y \) in terms of a common variable. Let \( y = 4k \) for some scalar \( k \): \[ x = 3k \] 6. **Choose a Simple Value for k**: To find a specific vector, we can choose \( k = 1 \): \[ x = 3 \quad \text{and} \quad y = 4 \] 7. **Write the Perpendicular Vector**: Thus, the vector that is perpendicular to \( 4\hat{i} - 3\hat{j} \) is: \[ \vec{B} = 3\hat{i} + 4\hat{j} \] ### Conclusion: The vector \( 3\hat{i} + 4\hat{j} \) is perpendicular to \( 4\hat{i} - 3\hat{j} \).

To find a vector that is perpendicular to the vector \( \vec{A} = 4\hat{i} - 3\hat{j} \), we can use the property that the dot product of two perpendicular vectors is zero. ### Step-by-Step Solution: 1. **Define the Perpendicular Vector**: Let the vector we are looking for be \( \vec{B} = x\hat{i} + y\hat{j} \). 2. **Set Up the Dot Product**: ...
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Knowledge Check

  • The unit vector perpendicular to the vectors hati-hatj and hati +hatj forming a right handed system is

    A
    `hatk`
    B
    `-hatk`
    C
    `(hati-hatj)/(sqrt(2))`
    D
    `(hati+hatj)/(sqrt(2))`
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