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A particle is moving along a circular al...

A particle is moving along a circular along a circular path of radius 5 m with a uniform speed `5ms^(-1)`. What will be the average acceleration when the particle completes half revolution?

Text Solution

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`t = (piR)/(v) = (pi xx 5)/(5) = pi sec`
`Delta vecv = (-5 hati) - (5hati) = -10 hati`
`veca_("avg") = (Delta vecv)/(t) = (-10hati)/(pi) rArr |veca _("avg")| = (10)/(pi) m//s^(2)`
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