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In an experiment, four quantities a,b,c ...

In an experiment, four quantities a,b,c and d are measured with percentage error `1%, 2%, 3%` and `4%` respectively. Quantity P is calculated `P = (a^(3)b^(2))/(cd)%`. Error in P is

A

`4%`

B

`14%`

C

`10%`

D

`7%`

Text Solution

Verified by Experts

The correct Answer is:
B
P =` (a^(3)b^(2))/(cd) rArr (DeltaP)/(P) xx 100`
`" "= pm ( 3(Deltaa)/(a) + 2 (Delta b)/(b) + (Delta c)/(c ) + (Delta d)/(d)) xx 100`
`= pm ( 3xx 1 + 2xx 2 + 3 +4) = pm 14%`
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Knowledge Check

  • A physical quantitiy X is related to four measurable quantities, a,b,c and d as give X=a^(2)b^(3)c^(5//2)d^(-2) . The percentage error in the measurement of a,b,c and d are 1%,2%,2% and 4% respectively. What is the percentage error in quantitiy X?

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