`CH_(3)CH_(2)CH(CHO)CH_(2)CH_(3) and`
`CH_(3)CH(CHO) CH_(2)CH_(2)CH_(3)` are :-

Options

A. Chain isomer
B. Position isomer
C. Metamerism
D. Functional isomer

Answer

To determine the type of isomerism exhibited by the compounds \( CH_3CH_2CH(CHO)CH_2CH_3 \) and \( CH_3CH(CHO)CH_2CH_2CH_3 \), we will follow these steps:

### Step 1: Identify the Functional Groups
Both compounds contain the aldehyde functional group (-CHO). This indicates that they are both aldehydes.

### Step 2: Analyze the Molecular Formula
We need to check if both compounds have the same molecular formula.
- For \( CH_3CH_2CH(CHO)CH_2CH_3 \):
- Count the carbon (C), hydrogen (H), and oxygen (O) atoms:
- C: 5
- H: 10
- O: 1
- Molecular formula: \( C_5H_{10}O \)

- For \( CH_3CH(CHO)CH_2CH_2CH_3 \):
- Count the carbon (C), hydrogen (H), and oxygen (O) atoms:
- C: 5
- H: 10
- O: 1
- Molecular formula: \( C_5H_{10}O \)

Both compounds have the same molecular formula \( C_5H_{10}O \).

### Step 3: Determine the Type of Isomerism
Now we need to determine the type of isomerism:
- **Functional Isomerism**: This occurs when compounds have the same molecular formula but different functional groups. Since both compounds are aldehydes, they do not exhibit functional isomerism.
- **Position Isomerism**: This occurs when the functional group is in different positions on the carbon chain. In this case, both compounds have the -CHO group, but they are located at different positions in the carbon chain.
- **Chain Isomerism**: This occurs when the carbon skeleton differs in arrangement (i.e., the branching of the carbon chain).

### Step 4: Conclusion
Given that both compounds are aldehydes and have the same molecular formula but differ in the arrangement of the carbon skeleton, they are classified as **chain isomers**.

### Final Answer
The compounds \( CH_3CH_2CH(CHO)CH_2CH_3 \) and \( CH_3CH(CHO)CH_2CH_2CH_3 \) are **chain isomers**.

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