`KO_(2)` is-

Options

A. Normal oxide
B. Super oxide
C. Suboxide
D. Peroxide

Answer

To determine what \( KO_2 \) is, we can follow these steps:

### Step 1: Identify the elements in \( KO_2 \)
- \( KO_2 \) consists of potassium (K) and oxygen (O).

**Hint:** Look at the periodic table to identify the elements and their properties.

### Step 2: Determine the group of potassium
- Potassium (K) is an alkali metal and belongs to Group 1 of the periodic table, which is part of the S-block elements.

**Hint:** Recall that alkali metals are found in Group 1 and have similar properties.

### Step 3: Analyze the oxidation states
- The oxidation state of potassium (K) in \( KO_2 \) is +1 because alkali metals typically have a +1 oxidation state.
- For the oxygen in \( KO_2 \), it is in the form of superoxide. In superoxides, the oxygen molecule \( O_2 \) carries a -1 charge overall.

**Hint:** Remember that in superoxides, the \( O_2 \) unit has a unique charge distribution.

### Step 4: Classify \( KO_2 \)
- Since \( KO_2 \) contains the superoxide ion \( O_2^{2-} \), where the overall charge is -1, it is classified as a superoxide.

**Hint:** Consider how the presence of \( O_2^{2-} \) affects the classification of the compound.

### Conclusion
- Therefore, \( KO_2 \) is a superoxide.

**Final Answer:** \( KO_2 \) is a superoxide.