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Oxidation state of nitrogen is incorrect...

Oxidation state of nitrogen is incorrectly given for:

A

`{:("Compound","Oxidation State"),([Co(NH_(3))_(5)Cl]Cl_(2),-3):}`

B

`{:("Compound","Oxidation State"),(NH_(2)OH,-1):}`

C

`{:("Compound","Oxidation State"),((N_(2)H_(5))_(2)SO_(4),+2):}`

D

`{:("Compound","Oxidation State"),(Mg_(3)N_(2),-3):}`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the oxidation state of nitrogen in various compounds, we will analyze each option step by step. ### Step 1: Analyze the first compound, Co(NH3)5Cl2 1. **Identify the overall charge**: The complex has a counter ion of Cl2, which indicates that the overall charge of the complex is +2. 2. **Set up the equation**: Let the oxidation state of cobalt (Co) be \(X\). The ammonia (NH3) is a neutral ligand, contributing 0 to the charge. The chlorine (Cl) contributes -1 for each Cl atom. \[ X + 5(0) + (-1) = +2 \] Simplifying this gives: \[ X - 1 = +2 \implies X = +3 \] 3. **Conclusion**: The oxidation state of cobalt is +3, which is correctly given. ### Step 2: Analyze the second compound, NH2OH (Hydroxylamine) 1. **Identify the overall charge**: NH2OH is a neutral molecule, so the overall oxidation state must be 0. 2. **Set up the equation**: Let the oxidation state of nitrogen be \(X\). \[ X + 3(+1) + (-2) = 0 \] Simplifying this gives: \[ X + 3 - 2 = 0 \implies X + 1 = 0 \implies X = -1 \] 3. **Conclusion**: The oxidation state of nitrogen is -1, which is correctly given. ### Step 3: Analyze the third compound, N2H5SO4 1. **Identify the overall charge**: N2H5SO4 is a neutral molecule, so the overall oxidation state must be 0. 2. **Set up the equation**: Let the oxidation state of nitrogen be \(X\). \[ 2X + 5(+1) + (-2) = 0 \] Simplifying this gives: \[ 2X + 5 - 2 = 0 \implies 2X + 3 = 0 \implies 2X = -3 \implies X = -\frac{3}{2} \] However, since we have 2 nitrogen atoms, we can also express this as: \[ 4X + 10 - 2 = 0 \implies 4X + 8 = 0 \implies 4X = -8 \implies X = -2 \] 3. **Conclusion**: The oxidation state of nitrogen is -2, but it is incorrectly given as +2. ### Step 4: Analyze the fourth compound, Mg3N2 1. **Identify the overall charge**: Mg3N2 is a neutral compound, so the overall oxidation state must be 0. 2. **Set up the equation**: Let the oxidation state of nitrogen be \(X\). \[ 3(+2) + 2X = 0 \] Simplifying this gives: \[ 6 + 2X = 0 \implies 2X = -6 \implies X = -3 \] 3. **Conclusion**: The oxidation state of nitrogen is -3, which is correctly given. ### Final Conclusion: The oxidation state of nitrogen is incorrectly given for the compound **N2H5SO4**, where it should be -2 but is incorrectly stated as +2.
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Knowledge Check

  • The oxidation state of nitrogen is highest in

    A
    `N_(3)H`
    B
    `NH_(3)`
    C
    `NH_(2)OH`
    D
    `N_(2)H_(4)`
  • One mole of N_(2)H_(4) loses ten moles of electrons to form a new compound A . Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in A ? (There is no change in the oxidation state of hydrogen.)

    A
    `-1`
    B
    `-3`
    C
    `+3`
    D
    `+5`
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