Standard heat of formation of `CH_(4)(g), CO_(2)(g)` and `H_(2)O(l)` are -75, -393.5, -286 kJ respectively. Find out the change in enthalpy for the reaction. `CH_(4)(g)+2O_(2)(g)rarr CO_(2)(g)+2H_(2)O(l)`

Explanation

To find the change in enthalpy (ΔH) for the reaction:

\[ \text{CH}_4(g) + 2\text{O}_2(g) \rightarrow \text{CO}_2(g) + 2\text{H}_2\text{O}(l) \]

we will use the standard heats of formation provided:

- ΔH°f for CH₄(g) = -75 kJ/mol
- ΔH°f for CO₂(g) = -393.5 kJ/mol
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