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The heat of combustion of carbon and mon...

The heat of combustion of carbon and monoxide are -394 and -285 KJ `mol^(-1)` respectively. The heat of formation of CO in KJ `mol^(-1)` is :-

A

`+109`

B

`-109`

C

`+218`

D

`-218`

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The correct Answer is:
To determine the heat of formation of carbon monoxide (CO) using the given heats of combustion, we can follow these steps: ### Step 1: Write the combustion reactions 1. The combustion of carbon (C) to form carbon dioxide (CO₂): \[ C + O_2 \rightarrow CO_2 \quad \Delta H_1 = -394 \, \text{kJ/mol} \] 2. The combustion of carbon monoxide (CO) to form carbon dioxide (CO₂): \[ 2CO + O_2 \rightarrow 2CO_2 \quad \Delta H_2 = -285 \, \text{kJ/mol} \] ### Step 2: Write the formation reaction of CO The formation of carbon monoxide (CO) from its elements is represented as: \[ C + \frac{1}{2} O_2 \rightarrow CO \quad \Delta H_f = ? \] ### Step 3: Use Hess's Law According to Hess's Law, the total enthalpy change for a reaction is the sum of the enthalpy changes for the individual steps. We can manipulate the combustion reactions to find the heat of formation of CO. 1. From the first combustion reaction, we have: \[ C + O_2 \rightarrow CO_2 \quad \Delta H_1 = -394 \, \text{kJ/mol} \] 2. From the second combustion reaction, we need to reverse it to express the formation of CO: \[ CO_2 \rightarrow 2CO + O_2 \quad \Delta H_2 = +285 \, \text{kJ/mol} \] (Note: Reversing the reaction changes the sign of ΔH) ### Step 4: Combine the reactions Now, we can add these two reactions: - The first reaction (combustion of C) produces CO₂. - The second reaction (reversed combustion of CO) consumes CO₂. Adding these gives: \[ C + O_2 \rightarrow CO_2 \quad (-394 \, \text{kJ/mol}) \\ CO_2 \rightarrow 2CO + O_2 \quad (+285 \, \text{kJ/mol}) \] When we add these, we can cancel out CO₂ and O₂: \[ C + \frac{1}{2} O_2 \rightarrow CO \] ### Step 5: Calculate the heat of formation Now we can calculate the heat of formation of CO: \[ \Delta H_f = \Delta H_1 + \Delta H_2 = -394 + 285 \] \[ \Delta H_f = -109 \, \text{kJ/mol} \] ### Final Answer The heat of formation of carbon monoxide (CO) is: \[ \Delta H_f = -109 \, \text{kJ/mol} \]
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ALLEN-THERMODYNAMICS -EXERCISE -3
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  2. If enthalpies of formation of C(2)H(4)(g),CO(2)(g) and H(2)O(l) at 25^...

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  3. The heat of combustion of carbon and monoxide are -394 and -285 KJ mol...

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  4. When a certain amount of ethylene was combusted, 6226 kJ heat was evol...

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  5. Find out the heat evolved in combustion if 112 litre (at 1 atm, 273 K)...

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  6. A person requires 2870 kcal of energy to lead normal daily life. If he...

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  7. On complete combustion of 2 gm methane 26575 cals of heat is generated...

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  8. X gm of ethanal was subjected to combustion in a bomb calorimeter and ...

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  9. The following are heats of reactions : (A) DeltaH(f)^(@) of H(2)O(l)...

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  10. The enthalpy combustion of a substance

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  12. In the combustion of 0.4 g. of CH(4) 0.25 Kcal. Of heat is liberated. ...

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  13. If C(6)H(12)O(6)(s) +6O(2)(g) to 6CO(2)(g)+6H(2)O (l), triangleH=680 K...

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  14. Which of the following equations corresponds to the enthalpy of combus...

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  15. Heat of formation of CO2 is 94.0 K.cal. What would be thequantity of h...

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  16. The amount of heat liberated when one mole of NH(4)OH reacts with one ...

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  17. If H^(+)+OH^(-)to H(2)O(l)+13.7 Kcal, then the value of heat of neutra...

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  18. The heat of neutralisation of a strong dibasic acid in dilute solution...

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  19. The temperature of a 5mL of strong acid increases by 5^(@) when 5 mL o...

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