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Which of the following molecules has bot...

Which of the following molecules has both `p_(pi)-p_(pi) and p_(pi)-d_(pi)` bonds

A

`XeO_(2)F_(2)`

B

`SO_(2)Cl_(2)`

C

`SO_(3)`

D

`XeO_(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which molecule has both \( p_{\pi}-p_{\pi} \) and \( p_{\pi}-d_{\pi} \) bonds, we will analyze the bonding in the given options, focusing on the molecule \( SO_3 \) (sulfur trioxide). ### Step-by-Step Solution: 1. **Identify the Central Atom**: - In \( SO_3 \), the central atom is sulfur (S). 2. **Determine the Valence Electrons**: - Sulfur has an atomic number of 16. Its electronic configuration is \( [Ne]3s^2 3p^4 \). Therefore, sulfur has 6 valence electrons (2 from \( 3s \) and 4 from \( 3p \)). 3. **Calculate the Hybridization**: - The formula for hybridization is given by: \[ \text{Hybridization} = \frac{1}{2} \left( \text{Number of valence electrons of central atom} + \text{Number of monovalent atoms surrounding it} \right) \] - In \( SO_3 \), there are 3 oxygen atoms surrounding sulfur. - Therefore, the hybridization of sulfur in \( SO_3 \) is: \[ \text{Hybridization} = \frac{1}{2} \left( 6 + 0 \right) = 3 \quad \text{(which corresponds to } sp^2 \text{ hybridization)} \] 4. **Determine the Type of Bonds Formed**: - In \( SO_3 \), sulfur uses its \( sp^2 \) hybridized orbitals to form sigma bonds with the three oxygen atoms. - The remaining \( p \) orbital on sulfur can form \( p_{\pi}-p_{\pi} \) bonds with the \( p \) orbitals of oxygen. 5. **Check for \( p_{\pi}-d_{\pi} \) Bonds**: - Sulfur also has vacant \( d \) orbitals (3d), which can participate in bonding. - In \( SO_3 \), the \( p \) orbital of sulfur can overlap with the \( d \) orbitals of another atom (if present) to form \( p_{\pi}-d_{\pi} \) bonds. 6. **Conclusion**: - Thus, in \( SO_3 \), there are both \( p_{\pi}-p_{\pi} \) bonds (between sulfur and oxygen) and \( p_{\pi}-d_{\pi} \) bonds (due to the involvement of sulfur's vacant \( d \) orbitals). - Therefore, the molecule that has both types of bonds is \( SO_3 \). ### Final Answer: The molecule that has both \( p_{\pi}-p_{\pi} \) and \( p_{\pi}-d_{\pi} \) bonds is **\( SO_3 \)**.
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