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The distance of the point (-2,6) from th...

The distance of the point (-2,6) from the line 3x`-`4y`-` 10=0

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To find the distance of the point (-2, 6) from the line given by the equation \(3x - 4y - 10 = 0\), we can use the distance formula from a point to a line. The formula for the distance \(D\) from a point \((x_1, y_1)\) to a line in the form \(Ax + By + C = 0\) is given by: \[ D = \frac{|Ax_1 + By_1 + C|}{\sqrt{A^2 + B^2}} \] ### Step-by-Step Solution ...
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Knowledge Check

  • Find the distance of the point (3,-5) from the line 3x - 4y - 26 =0 .

    A
    `(3)/(5)`
    B
    `(5)/(3)`
    C
    `(2)/(3)`
    D
    `(3)/(4)`
  • The distance of the point (2, 3) from the line 4x-3y+26=0 is same as its distance from the line 3x-4y+p=0 . The value of p can be

    A
    5
    B
    25
    C
    31
    D
    `-31`
  • What is the distance of the point (2,3,4) from the plane 3x-6y + 2z + 11 = 0

    A
    1 unit
    B
    2 unit
    C
    3 unit
    D
    4 unit
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