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Find the ratio of de Broglie wavelength ...

Find the ratio of de Broglie wavelength of a proton and as `alpha`-particle which have been accelerated through same potential difference.

A

`2`

B

`2sqrt2`

C

`1/(2sqrt2)`

D

`sqrt2`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • An electron of mass m when accelerated through a potential difference V has de - Broglie wavelength lambda . The de - Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be

    A
    `(lambda m)/(M)`
    B
    `lambda sqrt((m)/(M))`
    C
    `(lambda M)/(m)`
    D
    `lambda sqrt((M)/(m))`

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