Which of the following is maximum soluble in organic solvent :-

Options

A. LiF
B. LiCl
C. LiBr
D. LiI

Explanation

To determine which of the following lithium halides is maximum soluble in organic solvents, we need to consider the covalent character of the compounds. The solubility of a compound in organic solvents is generally higher for compounds that exhibit more covalent character.

### Step-by-step Solution:

1. **Identify the Compounds**: We are looking at the lithium halides: Lithium Fluoride (LiF), Lithium Chloride (LiCl), Lithium Bromide (LiBr), and Lithium Iodide (LiI).

2. **Understand Covalent Character**: Covalent character in ionic compounds increases with the size of the anion. Larger anions tend to have more polarizable electron clouds, which enhances covalent character.

3. **Order of Anion Size**: The size of the halide anions from smallest to largest is:
- Fluoride (F⁻) < Chloride (Cl⁻) < Bromide (Br⁻) < Iodide (I⁻)

4. **Covalent Character Order**: According to Fajans' rules, the covalent character of the lithium halides increases with the size of the anion:
- LiF < LiCl < LiBr < LiI

5. **Solubility in Organic Solvents**: Since organic solvents tend to dissolve compounds with higher covalent character, we can conclude:
- LiI (Lithium Iodide) has the highest covalent character and thus is the most soluble in organic solvents.

6. **Final Conclusion**: Therefore, the lithium halide that is maximum soluble in organic solvent is **Lithium Iodide (LiI)**.

### Answer: Lithium Iodide (LiI)

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