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What percentage of progenies when there ...

What percentage of progenies when there is marriage between colourblind father's son and colourblind mother's daughter -

A

50% sons colour blind

B

50% daughters carriers

C

50% daughters normal

D

All of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of determining the percentage of progenies when there is a marriage between a colorblind father's son and a colorblind mother's daughter, we can follow these steps: ### Step 1: Understand the Genetic Background Color blindness is a sex-linked recessive trait carried on the X chromosome. Males have one X and one Y chromosome (XY), while females have two X chromosomes (XX). A male with color blindness has the genotype XcY (where Xc represents the X chromosome with the colorblind allele), and a female who is a carrier has the genotype XcX (where Xc is the X chromosome with the colorblind allele and X is the normal allele). ### Step 2: Identify the Genotypes of the Parents - The father (colorblind) has the genotype: **XcY** - The mother (colorblind) has the genotype: **XcX** ### Step 3: Determine the Possible Gametes - The father can produce two types of gametes: **Xc** and **Y**. - The mother can produce two types of gametes: **Xc** and **X**. ### Step 4: Set Up the Punnett Square We can set up a Punnett square to visualize the possible combinations of gametes from both parents: | | **Xc** (from mother) | **X** (from mother) | |---------|-----------------------|----------------------| | **Xc** (from father) | XcXc (carrier female) | XcX (normal female) | | **Y** (from father) | XcY (colorblind male) | XY (normal male) | ### Step 5: Analyze the Results From the Punnett square, we can see the following combinations: 1. XcXc - Carrier Female 2. XcX - Normal Female 3. XcY - Colorblind Male 4. XY - Normal Male ### Step 6: Calculate the Percentages Now we can calculate the percentages of each type of progeny: - 1 Carrier Female (XcXc) = 25% - 1 Normal Female (XcX) = 25% - 1 Colorblind Male (XcY) = 25% - 1 Normal Male (XY) = 25% ### Final Result - 50% of the progenies will be colorblind males (XcY). - 50% of the progenies will be normal males (XY) and carrier females (XcX). - Thus, the percentage of progenies that are colorblind is **25%**. ### Summary The percentage of progenies that will be colorblind when there is a marriage between a colorblind father's son and a colorblind mother's daughter is **25%**. ---
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