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An octahedral complex having formula Ma(...

An octahedral complex having formula `Ma_(2)b_(2)C_(2)`, which of the following combination is possible to exhibitd optical isomerism

A

`a = Cl^(-) " " B "&" C = (en)`

B

a & b & `c = EDTA`

C

a & `b = C_(2)O_(4)^(-2), " " c = en`

D

`a = H_(2)O, b = NH_(3), C = Cl^(-)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which octahedral complex of the formula \( MA_2B_2C_2 \) can exhibit optical isomerism, we need to analyze the possible combinations of ligands and their spatial arrangements. Optical isomerism occurs when a molecule can exist in two non-superimposable mirror images, known as enantiomers. ### Step-by-Step Solution: 1. **Understanding the Formula**: The formula \( MA_2B_2C_2 \) indicates that the metal \( M \) is coordinated to two types of ligands \( A \), \( B \), and \( C \). Each type of ligand appears twice. 2. **Identifying Ligands**: We need to evaluate the combinations of ligands given in the options to see if they can create a chiral environment. 3. **Analyzing Each Option**: - **Option A**: \( A = Cl_2 \), \( B = en \), \( C = en \) - Here, both \( B \) and \( C \) are identical bidentate ligands (ethylenediamine). The arrangement will lead to a symmetrical structure, which cannot produce optical isomers. - **Option B**: \( A = EDTA \), \( B = EDTA \), \( C = EDTA \) - All ligands are identical (EDTA), leading to a symmetrical structure. No optical isomerism is possible. - **Option C**: \( A = oxalato \), \( B = oxalato \), \( C = en \) - Both \( A \) and \( B \) are bidentate ligands (oxalato), and \( C \) is also a bidentate ligand (en). The arrangement will not create a chiral center, as the two oxalato ligands will create a symmetrical structure. - **Option D**: \( A = H_2O \), \( B = NH_3 \), \( C = Cl \) - In this case, we have two different types of monodentate ligands (water and ammonia) and one type of halide ligand (chloride). If we arrange the ligands in a cis configuration, we can create a chiral environment. The mirror image of this arrangement will not be superimposable on the original, thus allowing for optical isomerism. 4. **Conclusion**: The only combination that allows for optical isomerism is **Option D**, which consists of two water molecules, two ammonia molecules, and two chloride ions. ### Final Answer: The correct option that can exhibit optical isomerism is **Option D**.

To determine which octahedral complex of the formula \( MA_2B_2C_2 \) can exhibit optical isomerism, we need to analyze the possible combinations of ligands and their spatial arrangements. Optical isomerism occurs when a molecule can exist in two non-superimposable mirror images, known as enantiomers. ### Step-by-Step Solution: 1. **Understanding the Formula**: The formula \( MA_2B_2C_2 \) indicates that the metal \( M \) is coordinated to two types of ligands \( A \), \( B \), and \( C \). Each type of ligand appears twice. 2. **Identifying Ligands**: We need to evaluate the combinations of ligands given in the options to see if they can create a chiral environment. ...
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Knowledge Check

  • Which of the following complex species is not expected to exhibit optical isomerism ?

    A
    `[Co(en) (NH_(3))_(2) Cl_(2)]^(+)`
    B
    `[Co(en)_(3)]^(3+)`
    C
    `[Co(en)_(2) Cl_(2)]^(+)`
    D
    `[Co(NH_(3))_(3)Cl_(3)]`
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