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In a regular polygon of n sides, each co...

In a regular polygon of `n` sides, each corner is at a distance `r` from the centre. Identical charges each of magnitude `q` are placed at corners. The field at the centre is

A

0

B

`((n-1)kQ)/(r^(2))`

C

`(m)/(n-1)k(Q)/(r^(2))`

D

`(n-1)/(n)k(Q)/(r^(2))` where, `k=1//4 pi epsilon_(0)`

Text Solution

AI Generated Solution

To find the electric field at the center of a regular polygon with \( n \) sides, where identical charges \( q \) are placed at each corner, we can follow these steps: ### Step 1: Understand the Configuration In a regular polygon with \( n \) sides, the charges are symmetrically placed at each vertex. Each charge \( q \) is at a distance \( r \) from the center of the polygon. ### Step 2: Calculate the Electric Field Due to One Charge The electric field \( E_0 \) due to a single charge \( q \) at a distance \( r \) from the charge is given by the formula: \[ ...
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Knowledge Check

  • In a regular polygon of n sides, each corner is at a distance r from the centre. Identical charges are placed at (n-1) corners. At the centre, the intensity is E and the potential is V . The ratio V//E has magnitude

    A
    rn
    B
    `r(n-1)`
    C
    `(n-1)//r`
    D
    `r(n-1)//n`
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