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The straight line x/a+y/b=1 cuts the axe...

The straight line `x/a+y/b=1` cuts the axes in A and B and a line perpendicular to AB cuts the axes in P and Q. Find the locus of the point of intersection of AQ and BP .

Text Solution

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The correct Answer is:
`x^2+y^2-ax - by = 0 `
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Knowledge Check

  • The line x/a-y/b=1 cuts the x-axis at P. The equation of the line through P and perpendicular to the given line is

    A
    (a) `x+y=ab`
    B
    (b) `x+y=a+b`
    C
    (c) `ax+by=a^(2)`
    D
    (d) `bx+ay=b^(2)`

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