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The density of nitrogen gas is maximum a...

The density of nitrogen gas is maximum at:

A

STP

B

273 K and 2 atm

C

546 K and 1 atm

D

546 and 2 atm

Text Solution

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To determine the temperature at which the density of nitrogen gas is maximum, we can use the relationship between density, pressure, and temperature. The density of a gas can be expressed using the ideal gas law and the formula for density. ### Step-by-Step Solution: 1. **Understand the Ideal Gas Law**: The ideal gas law is given by the equation: \[ PV = nRT \] where \(P\) is pressure, \(V\) is volume, \(n\) is the number of moles, \(R\) is the ideal gas constant, and \(T\) is temperature. 2. **Express Moles in Terms of Mass**: The number of moles \(n\) can be expressed as: \[ n = \frac{m}{M} \] where \(m\) is the mass of the gas and \(M\) is the molar mass. 3. **Substituting Moles into the Ideal Gas Law**: Substituting \(n\) into the ideal gas law gives: \[ PV = \frac{m}{M}RT \] 4. **Rearranging for Density**: The density \(\rho\) is defined as: \[ \rho = \frac{m}{V} \] Therefore, we can rearrange the ideal gas equation to express density: \[ P = \frac{m}{V} \cdot \frac{RT}{M} \implies \rho = \frac{PM}{RT} \] 5. **Finding the Relationship**: From the equation \(\rho = \frac{PM}{RT}\), we can see that density \(\rho\) is directly proportional to pressure \(P\) and inversely proportional to temperature \(T\): \[ \rho \propto \frac{P}{T} \] 6. **Analyzing Given Conditions**: We need to evaluate the conditions at: - STP: \(P = 1 \, \text{atm}, T = 298 \, \text{K}\) - \(273 \, \text{K}\) and \(280 \, \text{K}\) - \(546 \, \text{K}\) and \(180 \, \text{K}\) 7. **Calculating Density Ratios**: For each condition, we can calculate the density ratio: - At STP: \(\rho \propto \frac{1}{298}\) - At \(273 \, \text{K}\): \(\rho \propto \frac{1}{273}\) - At \(280 \, \text{K}\): \(\rho \propto \frac{1}{280}\) - At \(546 \, \text{K}\): \(\rho \propto \frac{1}{546}\) 8. **Comparing Values**: The smaller the denominator, the larger the density. Thus: - \(\frac{1}{273}\) is larger than \(\frac{1}{280}\) and \(\frac{1}{546}\). - Therefore, the maximum density occurs at \(273 \, \text{K}\). ### Conclusion: The density of nitrogen gas is maximum at \(273 \, \text{K}\).
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Knowledge Check

  • To save on helium costs, a balllon is inflated with both helium and nitrogen gas. Between the two gases, the ballon can be inflated up to 8 liters in volume. The density of helium is 0.20 gram per liter, and the density of nitrogen is 1.30 grams per liter. The ballon must be filled so that the volumetric average density of the ballon is lower than that of air, which has a density of 1.20 grams per liter. Which if the following system of inequalities best describes how the ballon will be filled, if x represent the number in liters of helium and y represents the number of liters of nitrogen?

    A
    `{(x+ygt8), (20x+130ygt120):}`
    B
    `{(x+y=8), ((0.2x+1.30y)/(2)lt1.20):}`
    C
    `{(x+y=47), (0.78x+1.07y=45.94):}`
    D
    `[(x+yle8), (0.20x+1.30ylt1.20):}`
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