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A weak acid HA of concentration 0.001 mi...

A weak acid HA of concentration 0.001 mile/litre have conductance 2x`10^(-5)Scm^(-1)` and molar conductivity at infinite dilution is 190 `Scm^2"mole"^(-1)` then value of `K_a` of weak acids id [X] x `10^(-6)`, then value of x in nearest integer is:

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The conductivity of a weak acid HA of concentration 0.001 mol L^(-1) is 2.0 xx 10^(-5)S cm^(-1) . If Lambda_(m)^(0)(H A) = 190 S cm^(2) mol^(-1) , the ionization constant (K_(a)) of HA is equal to ________ xx 10^(-6) . (Round off to the Nearest Integer)

Molar conductivity of a weak acid HA at infinite dilution is 345.8 cm^(2) mol^(-) calculate molar conductivity of 0.05 M HA solution

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  • The dissociation constant of a weak acid is 1.6xx10^(-5) and the molar conductivity at infinite dilution is 380xx10^(-4) S m^2mol^(-1) . If the cell constant is 0.01 m^(-1) then conductace of 0.1M acid solution is :

    A
    `1.52xx10^(-5)`S
    B
    1.52 S
    C
    `1.52xx10^(-3)`S
    D
    `1.52xx10^(-4)`S
  • The molar conductivity of 0.05 M solution of weak acid is 16.6Omega^(-1)cm^(-2)mol^(-1). Its molar conductivity at infinite dilution is 390.7Omega^(-1)cm^(-2)mol^(-1) . The degree of dissociation of weak acid is

    A
    0.24
    B
    0.42
    C
    0.042
    D
    0.024
  • The ionization constant of a weak acid is 1.6xx10^(-5) and the molar conducitvity at infinite dilutionis 380xx10^(-4)" S " m^(2) mol^(-1) . If the cell constant is 0.01 m^(-1) , then the conductance of 0.01 M solution is :

    A
    `1.52xx10^(-5)" S "`
    B
    `1.52" S "`
    C
    `1.52xx10^(-3)" S "`
    D
    `1.52xx10^(-4)" S "`
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