By using valence bond theory discuss the geometry aud magnetic nature of `[Cr(NH_3)_6]^(3+)` ion.

Explanation

The hybridisation and formation of `[Cr(NH_3)_6]^(3+)` ion is shhown as below :

The ion `Cr^(3+)` has two vacant d- orbitals. These orbitals. These orbitals get hybridised with one 4s and three 4p-orbitals resulting in `d^2 sp^3` hybridisation. Now the six vacant `d^2sp^3` hybrid orbitals are occupied by has octahedral geometry. Since there are three unpaired d - electrons, it is paramagnetic in nature.