If the velocity of the electron in Bohr's first orbit is `2. 19 xx 10 ^(5) ms ^(-1).` Calculate the de-Broglie wavelength associated with it .

Explanation

According to de-Broglie equation `lamda = ( h)/(mv)`
Where `m = 9. 11 xx 10 ^(-31) kg `
`v = 2. 19 xx 10 ^(6) ms ^(-1)`
`h = 6.63 xx 10 ^(-34) kg m ^(2) s ^(-1)`
`lamda = ( 6.63 xx 10 ^(-34) kg m ^(2) s ^(-1))/( ( 9. 11 xx 10 ^(-31) kg ) xx (2. 19 xx 10 ^(6) ms ^(-1)))= 3.32 xx 10 ^(-10) m = 332 pm.`