What is the pH of 0.1 M HCl ?

Explanation

The reaction may be written as
`HCl rarr H^(+)(aq) + Cl^(-)(aq)`
0.1 M
`[H^(+)] = [HCl] = 0.1 M = 10^(-1)M`
`therefore pH = -log [H_(3)O^(+)] = -log 10^(-1) = -(-log 10) = 1`
So, pH = 1