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A constant retarding force of 50 N is ap...

A constant retarding force of 50 N is applied to a body of mass 20 kg moving initially with a speed of `15m s^-1`. How long does the body take to stop ?

Text Solution

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We are given: `m = 20 kg implies F= -50 N implies u= 15ms^(-1) implies v=0`
We are to calculate: Stopping time, t
We know that, `F= ma implies a= (F)/(m)= (-50)/(20)= -2.5 ms^(-2)`
Also, `v= u+at implies 0+ 15+ (-2.5)t implies t= 6s`
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Knowledge Check

  • When a constant force is applied to a body, it moves with uniform

    A
    Acceleration
    B
    Velocity
    C
    Speed
    D
    Momentum

  • A force of 1 newton acts on a body of mass 1 kg. It will produce in the body

    A
    An acceleration of `100 cm//s^(2)`
    B
    A velocity of `1 m//s`
    C
    An acceleration of `980 cm//s^(2)`
    D
    A velocity of `980 cm//s`.

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