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Let alpha,betabe the roots of the equati...

Let `alpha,beta`be the roots of the equation `(x-a)(x-b)=c,c!=0` then the roots of the equation`(x-alpha)(x-beta)+c=0` are :

A

a) a,c

B

b) b,c

C

c) a, b

D

d) a+b, a+c

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • If alpha, beta are the roots of the equation (x-a) (x-b)=c and c ne 0 , then roots of the equation (x-alpha) (x-beta)+c=0 are

    A
    a,c
    B
    b,c
    C
    a,b
    D
    a+b,b+c

  • If alpha, beta be the roots of the equation (x-a)(x-b) + c = 0 (c ne 0) , then the roots of the equation (x-c-alpha)(x-c-beta)= c , are

    A
    a and b + c
    B
    a + c and b
    C
    a + c and b + c
    D
    a - b and b - c

  • Let alpha, and beta are the roots of the equation x^(2)+x +1 =0 then

    A
    `alpha^(2) +beta^(2) =4`
    B
    `(alpha - beta)^(2)=3`
    C
    `alpha^(3) +beta^(3)=2`
    D
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