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If we write 45 as sum of four numbers so...

If we write 45 as sum of four numbers so that when 2 is added to first number, 2 subtracted from second number, third multiplied by 2 and fourth divided by 2. we get the same result, then the four numbers are :

A

1, 8, 15, 21

B

8, 12, 5, 20

C

8, 12, 10, 15

D

2, 12, 5, 26

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we can follow these instructions: ### Step 1: Define the Variables Let the four numbers be \( a, b, c, \) and \( d \). ### Step 2: Set Up the Equation According to the problem, the sum of the four numbers is: \[ a + b + c + d = 45 \] ### Step 3: Set Up the Conditions The problem states that: 1. When 2 is added to the first number: \( a + 2 \) 2. When 2 is subtracted from the second number: \( b - 2 \) 3. When the third number is multiplied by 2: \( 2c \) 4. When the fourth number is divided by 2: \( \frac{d}{2} \) All these expressions are equal: \[ a + 2 = b - 2 = 2c = \frac{d}{2} \] ### Step 4: Express \( b, c, \) and \( d \) in terms of \( a \) From the first equality \( a + 2 = b - 2 \): \[ b = a + 4 \] From the second equality \( a + 2 = 2c \): \[ c = \frac{a + 2}{2} \] From the third equality \( a + 2 = \frac{d}{2} \): \[ d = 2(a + 2) = 2a + 4 \] ### Step 5: Substitute Back into the Sum Equation Now substitute \( b, c, \) and \( d \) back into the sum equation: \[ a + (a + 4) + \left(\frac{a + 2}{2}\right) + (2a + 4) = 45 \] ### Step 6: Simplify the Equation Combine like terms: \[ a + a + 4 + \frac{a + 2}{2} + 2a + 4 = 45 \] \[ 4a + 8 + \frac{a + 2}{2} = 45 \] Multiply the entire equation by 2 to eliminate the fraction: \[ 2(4a + 8) + (a + 2) = 90 \] \[ 8a + 16 + a + 2 = 90 \] \[ 9a + 18 = 90 \] ### Step 7: Solve for \( a \) Subtract 18 from both sides: \[ 9a = 72 \] Divide by 9: \[ a = 8 \] ### Step 8: Find \( b, c, \) and \( d \) Now substitute \( a \) back to find \( b, c, \) and \( d \): - \( b = a + 4 = 8 + 4 = 12 \) - \( c = \frac{a + 2}{2} = \frac{8 + 2}{2} = \frac{10}{2} = 5 \) - \( d = 2a + 4 = 2(8) + 4 = 16 + 4 = 20 \) ### Final Answer The four numbers are: \[ \boxed{8, 12, 5, 20} \]
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Knowledge Check

  • The sum of four numbers is 64. If you add 3 to first number , 3 is subtracted from the second number, the third is multiplied by 3 and the fourth is divided by 3, then all the results become equal. What is the difference between the largest and the smallest of the original numbers ?

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