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A person deposited a sum of Rs.6,000 in ...

A person deposited a sum of `Rs.6,000` in a bank at `5%` per annum simple interest. Another person deposited `Rs. 5,000` at `8%` per annum compound interest. After two years, the difference of their interests will be

A

`Rs. 230`

B

`Rs. 232`

C

`Rs. 832`

D

`Rs. 600`

Text Solution

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The correct Answer is:
To solve the problem, we need to calculate the simple interest earned by the first person and the compound interest earned by the second person after two years. Then, we will find the difference between these two amounts. ### Step 1: Calculate Simple Interest for the First Person The formula for Simple Interest (SI) is given by: \[ SI = \frac{P \times R \times T}{100} \] Where: - \( P \) = Principal amount (Rs. 6000) - \( R \) = Rate of interest (5%) - \( T \) = Time (2 years) Substituting the values into the formula: \[ SI = \frac{6000 \times 5 \times 2}{100} \] Calculating the above expression: \[ SI = \frac{6000 \times 10}{100} = \frac{60000}{100} = 600 \] So, the simple interest earned by the first person after 2 years is Rs. 600. ### Step 2: Calculate Compound Interest for the Second Person The formula for Compound Interest (CI) is: \[ A = P \left(1 + \frac{R}{100}\right)^T \] Where: - \( A \) = Amount after time \( T \) - \( P \) = Principal amount (Rs. 5000) - \( R \) = Rate of interest (8%) - \( T \) = Time (2 years) First, we calculate the amount \( A \): \[ A = 5000 \left(1 + \frac{8}{100}\right)^2 \] Calculating \( \frac{8}{100} \): \[ A = 5000 \left(1 + 0.08\right)^2 = 5000 \left(1.08\right)^2 \] Calculating \( (1.08)^2 \): \[ (1.08)^2 = 1.1664 \] Now substituting back: \[ A = 5000 \times 1.1664 = 5832 \] Now, we find the compound interest \( CI \): \[ CI = A - P = 5832 - 5000 = 832 \] So, the compound interest earned by the second person after 2 years is Rs. 832. ### Step 3: Calculate the Difference in Interests Now, we find the difference between the compound interest and the simple interest: \[ \text{Difference} = CI - SI = 832 - 600 = 232 \] Thus, the difference of their interests after two years is Rs. 232. ### Final Answer: The difference of their interests after two years is Rs. 232. ---
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Knowledge Check

  • A man deposited ₹ 6000 in a bank at 5% simple interest. Another man deposited 5000 at 8% compound interest. After 2 years, the difference of their interests will be

    A
    ₹ `230`
    B
    ₹ `232`
    C
    ₹ `600`
    D
    ₹ `832`
  • What sum will amount to Rs. 6,600 in 4 years at 8% per annum simple interest?

    A
    Rs. 6,000
    B
    Rs. 5,000
    C
    Rs 4,000
    D
    Rs 6,200
  • A person deposits Rs. 7000 rupees for 2 years at 8% per annum on simple interest and he deposits Rs. 10,000 for the same rate and same time on compounded interest. Then find the total interest earned by the person after 2 years.

    A
    Rs. 2784
    B
    Rs. 2460
    C
    Rs. 2889
    D
    Rs. 2680
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