Home
Class 11
PHYSICS
A particle moving along x-axis has accel...

A particle moving along x-axis has accelaration f, at time t , given by `f=f_0(1− t/ T ​ )` where `f_0` and T are constants . The particle at t=0 has zero velocity . In the time interval between t=0 and the instant when f=0, the particle's velocity `(nu_x)` is:

A

`1/2f_oT`

B

`f_oT`

C

`1/2f_oT^2`

D

`f_oT^o`

Text Solution

Verified by Experts

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • LAWS OF MOTION

    SARAS PUBLICATION|Exercise EXAMPLE|16 Videos

  • OSCILLATIONS AND WAVES

    SARAS PUBLICATION|Exercise EXAMPLE|40 Videos

Similar Questions

Explore conceptually related problems

The velocity of a particle is zero at t=0

The acceleration of a particle in ms^(-1) is given by a=3t^(2)+2t+2 where timer is in second If the particle starts with a velocity v=2ms^(-1) at t=0 then find the velocity at the end of 2s.

Knowledge Check

  • The position of a particle moving along a horizontal line of any time t is given by s(t)=3t^(2)-2t-8 . The time at which the particle is at rest is

    A
    `t=0`
    B
    `t=(1)/(3)`
    C
    `t=1`
    D
    `t=3`

  • The velocity v of a particle at time t is given by v = a t + \frac { b } { t + c } where a, b and c are constant. The dimensions of a, b and c respectively are

    A
    `[L^2, T and LT^2]`
    B
    `[LT^2, LT and L]`
    C
    `[L, LT and T^2]`
    D
    `[LT^-2, L and T]`

  • The position of a particle moving along a horizontal line of any time t is given by s(t)=3t^(2)-2t-8 . The time at which the particle is at rest is …………….. .

    A
    `t=0`
    B
    `t=(1)/(3)`
    C
    `t=1`
    D
    `t=3`

    • Similar Questions

    Explore conceptually related problems

    The position of a particle moving along a horizontal line of any time t is given by s(t)=3t^(2)-2t-8 . The time at which the particle is at rest is

    A particle movesin the X-Y plane with a constasnt acceleration of 1.5 m/s^2 in the direction making an angle of 37^0 with the X-axis.At t=0 the particle is at the orign and its velocity is 8.0 m/s along the X-axis. Find the velocity and the position of the particle at t=4.0 s.

    A particle moves in circle of radius 1.0 cm at a speed given by v=2.0 t where v is in cm/s and t in seconeds. A. find the radia accelerationof the particle at t=1 s. b. Findthe tangential acceleration at t=1s. c.Find the magnitude of the aceleration at t=1s.

    A particle moves along the x-axis in such a way that its coordinates x varies with time 't' according to the equation x=2-5t+6t^(2) . What is the initial velocity of the particle?

    The velocity of a particle is given by the equation, v = 2t^(2) + 5 cms^(-1) . Find the change in velocity of the particle during the time interval between t_(1) = 2s and t_(2) = 4s .

    Home
    Profile