Home
Class 12
MATHS
For the curve y = 5x - 2x^3, if x increa...

For the curve `y = 5x - 2x^3`, if x increases at te rate of 2units/s, then how fast is the slope of curve changing when x =3?

Answer

Step by step text solution for For the curve y = 5x - 2x^3, if x increases at te rate of 2units/s, then how fast is the slope of curve changing when x =3? by MATHS experts to help you in doubts & scoring excellent marks in Class 12 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • APPLICATION OF DERIVATIVES

    MODERN PUBLICATION|Exercise EXERCISE|433 Videos

  • APPLICATIONS OF THE INTEGRALS

    MODERN PUBLICATION|Exercise EXERCISE|211 Videos

Similar Questions

Explore conceptually related problems

The length x of a rectangle is decreasing at the rate of 2 cm/s and the width y is increasing at the rate of 2 cm/s. When x = 12 cm and y = 5 cm find the rate of change of (a) the perimeter

The length x of a rectangle is decreasing at the rate of 2 cm/s and the width y is increasing at the rate of 2 cm/s. When x = 12 cm and y = 5 cm find the rate of change of (b) the area of the rectangle .

Knowledge Check

  • Area betweenn the curve y = 4+3x-x^(2) and x - axis is square units is :

    A
    `(125)/3`
    B
    `125/4`
    C
    `125/6`
    D
    `125/8`

    • Similar Questions

    Explore conceptually related problems

    If equation of the curve is y^2=4x then find the slope of normal to the curve

    Sketch the curve y=(x-1)(x-2)(x-3) .

    A particle moves along the curve y = (2/3)x^3 +1 . Find the points on the curve at which y-coordinate is changing twice as fast as the x-coordinate.

    A particle moves along the curve 6y = x^3+2 . Find the points on the curve at which the y-coordinate is changing 8 times as fast as the x-coordinate.

    A particle moves along the curve 6y=x^(3)+2 . Find the points on the curve at which the y-coordinate is changing 8 times as fast as x-coordinate.

    The point on the curv3e y = sqrt(4x-3) -1, at which the slope of the tangent is 2/3 , is

    Find the slope of the tangent to curve y = x^3-x+1 at the point whose x-coordinate is 2.

    Home
    Profile