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A compound H(2)X with molecular weight 8...

A compound `H_(2)X` with molecular weight 80 is dissolved in a solvent having densit 0.4 g/mL. Assuming no change in volume upon dissolution, the molality of a 3.2 molar solution is

Text Solution

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The correct Answer is:
8
Let us consider, volume of solution =1 litre = 1000 mL
Weight of solvent `= 0.4 xx 1000 = 400 g ` Weight of solute = 80 g
Number of moles of solute `= 3.2 ` moles Molality of solution = (m)
`= ( w _(2) xx 1000)/( M w _(2) xx w _(1)) = ( n _(2) xx 1000)/( w _(1)) = ( 3.2 xx 1000)/( 400) = 8`
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