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First and second ionisation energies of ...

First and second ionisation energies of magnesium are 7.646 and 15.035 eV respectively. The amount of energy in kJ needed to convert all the atoms of magnesium into `Mg^(2+)` ions present in 12 mg of magnesium vapours is: 1.1, 1.5, 2, 0.5

A

1.1

B

1.5

C

2

D

0.5

Text Solution

Verified by Experts

The correct Answer is:
A
Total energy needed to convert one Mg atom into.
`Mg^(2+)(g) ` ion ` = IE_1 + IE_n = 22.681 eV =2188 kJ "mol"^(-1)`
12 mg of Mg ` = 0.5 xx 10^(-3) ` mole
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