Home
Class 11
CHEMISTRY
The heats of formation (Delta Hf^@) of t...

The heats of formation `(Delta H_f^@)` of the oxides of the third period, sodium to chlorine, are in kJ `"mol"^(-1)`

Based on these data, answer the following questions
Which oxide has maximum negative heat of formation per oxygen atom?

A

`P_4O_10`

B

`Al_2O_3`

C

`Na_2O`

D

`MgO`

Text Solution

Verified by Experts

The correct Answer is:
D
`MgO`
Promotional Banner

Topper's Solved these Questions

  • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

    BRILLIANT PUBLICATION|Exercise QUESTIONS (LEVEL-III ( Statement Type ))|5 Videos

  • CHEMICAL THERMODYNAMICS

    BRILLIANT PUBLICATION|Exercise LEVEL-III|52 Videos

  • ENVIRONMENTAL CHEMISTRY

    BRILLIANT PUBLICATION|Exercise QUESTIONS LEVEL-II (ASSERTION-REASON TYPE)|10 Videos

Similar Questions

Explore conceptually related problems

Electron gain enthalphy is the amount of energy involved when an isolated gaseous atom accepts an electron to form a monovalent anion the value of the electron gain enthalpy of halogens are given below: F : -328 KJ mol^(-1) Cl - 349 KJ mol^(-1) Br : -325 KJ mol^(-1) I : -295 KJ mol^(-1)Chlorine has more negative electron gain enthalpy than fluorine. why ?

The standard enthalpies of formation of H_(2)O(l) and CO_(2)(g) are respectively -286" kJ mol"^(-1) and -394" kJ mol"^(-1) . If the standard heat of combustion of CH_(4)(g)" is "-891" kJ mol"^(-1) , then the standard enthalpy of formation of CH_(4)(g) is

The formation of the oxide ion O^(2-) (g) requires first an exothermic and then an endothermic step as shown below, O(g)+ e^(-) = O^(-)(g), DeltaH^(@)= -142kJmol^(-1) O^(-)(g) +e^(-) =O^(2-)(g), DeltaH^(@)= 844 kJmol^(-1) This is because : oxygen is more electronegative, oxygen has high electron affinity, O^(-) ion will tend to resist the addition of another electron , O^(-) ion has comparatively larger size than oxygen atom

Which of the following statements about Ellingham diagram are true? i) Ellingham diagram normally consists of plots of Delta_(f)G^(@) Vs T for formation of oxides of elements (ii) Each plot will be straight lines at all temperatures iii) There is a point in a curve below which DeltaG is -ve and above this point the oxide decompose its own iv) Ellingham diagram is restricted to metal oxides v) Ellingham diagram does not say about kinetics of the reduction process vi) Ellingham diagram presumes that the reactants and products are in equilibrium

Assertion : Eventhough HF is a weak acid heat liberated during neutralisation with a strong base is more than 57 kJ mol^(-1) Reason : Hydration energy of F-is very large