What is the mass of urea required for making 2.5 kg of 0.25 molal aqueous solution?

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No. of moles of urea = 0.25 moles
Mass of solvent = 1 kg = 1000 g
Molar mass of urea = 60 g `mol""^(-1)`
Mass of urea in 1000 g of `H_2 O = 0.25 xx 60 = 15 g `
Total mass of solution = 1000 + 15 = 1015 g
1.015 kg solution contains 15 g urea
2.5 kg solution will contain `=(15 )/(1.015 ) xx 2.5 =37 g `
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