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The average atomic mass of a sample of a...

The average atomic mass of a sample of an element X is 16.2 `mu`. What is the percentage of each isotope `overset(18)underset(8)X` and `overset(18)underset(8)X` in the sample?

Text Solution

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Let the % of isotope 15X = x and % of isotope `""_(8)^(18)X = 100 - x` Average atomic mass of an element (X) = 16.2 Average atomic mass
` = (" Mass of "_(8)^(18)X xx "percentange of "_(8)^(18)X )/(100)`
` or 16.2 =(x xx 16 +(100 -x) xx 18)/( 100 )`
` or 16.2 = ( 16 x + 1800 - 18 x )/(100)`
` or 1620 = 16 x + 1800 - 18 x`
` or 1620 = - 2x + 1800 or 2 x = 1800 - 1620 `
`or 2 x = 180 `
` therefore x= (180 )/(2) = 90`
Thus % of isotope `""_(8)^(16) X = 90`% %
`% ` of isotope `""_(8)^(18)X= (100 -90) = 10 %`
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Knowledge Check

  • The average atomic mass of an element A is 16.2 u. There are two isotopes ""_(8)^(16) A and ""_(8)^(18)A of an element. What will be the percentage of these two isotopes in element A ?

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    D
    Methane
  • Isotopes are the atoms of same element, they have same atomic number but different mass numbers. Isotopes have different number of neutrons in their nucleus . If an element exists in two isotopes having atomic masses 'a' and 'b' in the ratio m:n, then average atomic mass will be (mxxa+nxxb)/(m+n) Different isotopes of same element have same position in the periodic table. the elemens which have single isotope are called monoisotropic elements. Greater is the percentage composition of an isotope, more will be its abundance in nature. .^(12)C and .^(14)C isotopes are found at 98% and 2% respectively in any sample. then, the number of .^(14)C atoms in 12g of the sample will be:

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