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The electronic configuration of elements...

The electronic configuration of elements A, B, C and D are (2, 8, 1), (2, 8, 2), (2, 8, 6) and (2, 8, 7) respectively. Which of them can make an ion with two negative charges?

A

A

B

B

C

C

D

D

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The correct Answer is:
To determine which of the elements A, B, C, and D can form an ion with two negative charges based on their electronic configurations, we will analyze each element step by step. ### Step 1: Analyze Element A - **Electronic Configuration**: (2, 8, 1) - **Valence Electrons**: 1 (the last shell has 1 electron) - **Ion Formation**: - Element A can lose 1 electron to achieve the stable electronic configuration of the nearest noble gas (which is Neon, with the configuration 2, 8). - **Ion Formed**: A can form A⁺ (a positive ion). ### Step 2: Analyze Element B - **Electronic Configuration**: (2, 8, 2) - **Valence Electrons**: 2 (the last shell has 2 electrons) - **Ion Formation**: - Element B can lose 2 electrons to achieve the stable electronic configuration of Neon (2, 8). - **Ion Formed**: B can form B²⁺ (a positive ion). ### Step 3: Analyze Element C - **Electronic Configuration**: (2, 8, 6) - **Valence Electrons**: 6 (the last shell has 6 electrons) - **Ion Formation**: - Element C can either lose 6 electrons or gain 2 electrons. It is easier for it to gain 2 electrons to achieve the stable configuration of Neon (2, 8). - **Ion Formed**: C can form C²⁻ (a negative ion with two negative charges). ### Step 4: Analyze Element D - **Electronic Configuration**: (2, 8, 7) - **Valence Electrons**: 7 (the last shell has 7 electrons) - **Ion Formation**: - Element D can gain 1 electron to achieve the stable configuration of Neon (2, 8). - **Ion Formed**: D can form D⁻ (a negative ion with one negative charge). ### Conclusion Based on the analysis: - **Element A** forms A⁺ (no negative charge). - **Element B** forms B²⁺ (no negative charge). - **Element C** forms C²⁻ (two negative charges). - **Element D** forms D⁻ (one negative charge). **Therefore, the element that can make an ion with two negative charges is Element C.** ---

To determine which of the elements A, B, C, and D can form an ion with two negative charges based on their electronic configurations, we will analyze each element step by step. ### Step 1: Analyze Element A - **Electronic Configuration**: (2, 8, 1) - **Valence Electrons**: 1 (the last shell has 1 electron) - **Ion Formation**: - Element A can lose 1 electron to achieve the stable electronic configuration of the nearest noble gas (which is Neon, with the configuration 2, 8). - **Ion Formed**: A can form A⁺ (a positive ion). ...
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MTG IIT JEE FOUNDATION-STRUCTURE OF THE ATOM-EXERCISE ( MULTIPLE CHOICE QUESTIONS -LEVEL-2)
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  2. The ratio between the neutrons in C and Si with respect to atomic mass...

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  3. An element M has an atomic mass 19 and atomic number 9. Its ion is rep...

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  4. Which of the following do not have the same number of valence electron...

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  5. The triad of nuclei that is isotonic is

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  6. The electronic configuration of elements A, B, C and D are (2, 8, 1), ...

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  7. According to Bohr's atomic model, as we move away from the nucleus

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  8. A has 9 protons, 9 electrons and 10 neutrons, B has 12 protons, 12 ele...

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  9. The number of electrons in carbon and fluorine are respectively

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  10. The increasing order for the values of e/m (charge/mass) is

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  11. How many total protons are found in one molecule of retinol (C(20H(30)...

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  12. An element A has atomic mass 39 and atomic number 19. Which one of the...

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  13. Which of the following has more electrons than neutrons?

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  14. Which of the following is an accurate illustration of a nitrogen atom?

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  15. Which of the following is a correct representation of Cl^(-)?

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  16. Two particles X and Y have the composition as shown in the table. ...

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  17. The relative atomic mass of naturally occurring chlorine is not a whol...

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  18. An element L has 9 protons and its valency is 1. Another element M has...

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  19. Schematic atomic structures of three elements are given below: Wh...

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  20. Vivek was given few models of atoms representing their structures. He ...

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