Home
Class 10
CHEMISTRY
Oxygen is prepared by catalytic decompos...

Oxygen is prepared by catalytic decomposition of potassium chlorate `(KClO_(3))`. Decomposition of potassium chlorate gives potassium chloride (KCl) and oxygen `(O_(2))`. The following reaction takes place : `2KClO_(3(s))to2KCl_((s))+3O_(2(g))`.
Mark the correct statement.

A

2 moles of `KClO_(3)` give 3 moles of oxygen.

B

1 mole of `KCIO_(3)` gives 1 mole of oxygen.

C

3 moles of oxygen are formed by 1 mole of `KCIO_(3)`.

D

200 g of `KCIO_(3)` gives 300 g of `O_(2)`.

Text Solution

Verified by Experts

The correct Answer is:
A
The reaction shows 2 moles of `KClO_(3)` = 3 moles of `O_(2)`.
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL REACTIONS AND EQUATIONS

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (VERY SHORT ANSWER TYPE)|16 Videos

  • CHEMICAL REACTIONS AND EQUATIONS

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (SHORT ANSWER TYPE)|19 Videos

  • CHEMICAL REACTIONS AND EQUATIONS

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (ASSERTION & REASON TYPE)|10 Videos

  • CHEMICAL EQUILIBRIUM

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (INTEGER/NUMERICAL VALUE TYPE)|5 Videos

  • FOOTSTEPS TOWARDS (NEET)

    MTG IIT JEE FOUNDATION|Exercise MCQ|45 Videos

Similar Questions

Explore conceptually related problems

Oxygen is prepared by catalytic decomposition of potassium chlorine (KClO_(3)) . Decomposition of potassium, chloride gives potassium chloride (KCl) and oxygen (O_(2)) . How many moles and how many grams of KClO_(3) are required to produce 2.4 mole O_(2) ?

Oxygen is prepared by the catalytic decomposition of potassium chlorate ( KClO_(3) ). Decomposition of potassium chlorate gives potassium chloride (KCl) and oxygen ( O_(2) ). If 2.4 mol of oxygen is needed for an experiment, how many grams of potassium chlorate must be decomposed ?

In the thermal decomposition of potassium chlorate given as 2KClO_(3)(s) to 2KCl(s)+3O_(2)(g) , law of mass action

Consider the following chemical reactions: 2KClO_3to 2KCl+3O_2 Is this decomposition reaction?

One mole of potassium chlorate (KClO_(3)) is thernally decomposed and excess of aluminum is aluminium oxide (Al_(2)O_(3)) are formed?

Numerical value of Deltan in the change: 2KClO_(3)hArr2KCl+3O_(2)