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Oxygen is prepared by catalytic decompos...

Oxygen is prepared by catalytic decomposition of potassium chlorate `(KClO_(3))`. Decomposition of potassium chlorate gives potassium chloride (KCl) and oxygen `(O_(2))`. The following reaction takes place : `2KClO_(3(s))to2KCl_((s))+3O_(2(g))`.
Mark the correct statement.

A

2 moles of `KClO_(3)` give 3 moles of oxygen.

B

1 mole of `KCIO_(3)` gives 1 mole of oxygen.

C

3 moles of oxygen are formed by 1 mole of `KCIO_(3)`.

D

200 g of `KCIO_(3)` gives 300 g of `O_(2)`.

Text Solution

Verified by Experts

The correct Answer is:
A

The reaction shows 2 moles of `KClO_(3)` = 3 moles of `O_(2)`.
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Oxygen is prepared by catalytic decomposition of potassium chlorine (KClO_(3)) . Decomposition of potassium, chloride gives potassium chloride (KCl) and oxygen (O_(2)) . How many moles and how many grams of KClO_(3) are required to produce 2.4 mole O_(2) ?

Oxygen is prepared by the catalytic decomposition of potassium chlorate ( KClO_(3) ). Decomposition of potassium chlorate gives potassium chloride (KCl) and oxygen ( O_(2) ). If 2.4 mol of oxygen is needed for an experiment, how many grams of potassium chlorate must be decomposed ?

Knowledge Check

  • Oxygen is prepared by catalytic decomposition of potassium chlorate (KClO_(3)) . Decomposition of potassium chlorate gives potassium chloride (KCl) and oxygen (O_(2)) . The following reaction takes place : 2KClO_(3(s))to2KCl_((s))+3O_(2(g)) . How many moles of KCIO_(3) are required to produce 2.4 moles of O_(2) ?

    A
    2
    B
    3
    C
    1.6
    D
    1.5
  • Oxygen is prepared by catalytic decomposition of potassium chlorate (KClO_(3)) . Decomposition of potassium chlorate gives potassium chloride (KCl) and oxygen (O_(2)) . The following reaction takes place : 2KClO_(3(s))to2KCl_((s))+3O_(2(g)) . How many grams of KClO_(3) are required to produce 128 grams of O_(2) ? [At. mass of O = 16 u, K = 39 u, Cl = 35.5 u]

    A
    196 g
    B
    200 g
    C
    122 g
    D
    327 g
  • In the thermal decomposition of potassium chlorate given as 2KClO_(3)(s) to 2KCl(s)+3O_(2)(g) , law of mass action

    A
    Cannot be applied directly
    B
    Can be applied
    C
    Can be applied at low temperature
    D
    Can be applied at high temp. and pressure
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