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Methane, ethane and propane are said to ...

Methane, ethane and propane are said to form a homologous series because all are

A

hydrocarbons

B

saturated hydrocarbons

C

aliphatic hydrocarbons

D

differ from each other by `-CH_(2)` group

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To answer the question, "Methane, ethane, and propane are said to form a homologous series because all are...", we need to understand the characteristics that define a homologous series in organic chemistry. ### Step-by-Step Solution: 1. **Definition of Homologous Series**: A homologous series is a group of organic compounds that have the same functional group and similar chemical properties, but differ from each other by a specific structural unit. **Hint**: Remember that a homologous series consists of compounds with similar properties but different structures. 2. **Identifying the Compounds**: - **Methane (CH₄)**: The simplest alkane with one carbon atom. - **Ethane (C₂H₆)**: The second member of the alkane series, with two carbon atoms. - **Propane (C₃H₈)**: The third member of the alkane series, with three carbon atoms. **Hint**: Identify the number of carbon atoms in each compound to understand their sequence in the series. 3. **Difference in Molecular Formula**: Each successive member of the series differs by a CH₂ unit: - From methane (CH₄) to ethane (C₂H₆), the difference is CH₂. - From ethane (C₂H₆) to propane (C₃H₈), the difference is also CH₂. **Hint**: Look for the pattern in the molecular formulas to see how each compound is related. 4. **General Formula for Alkanes**: The general formula for alkanes is CₙH₂ₙ₊₂, where n is the number of carbon atoms. For methane, ethane, and propane, the values of n are 1, 2, and 3 respectively. **Hint**: Familiarize yourself with the general formula for alkanes to see how it applies to the given compounds. 5. **Saturated Hydrocarbons**: Methane, ethane, and propane are saturated hydrocarbons, meaning they contain only single bonds between carbon atoms. **Hint**: Remember that saturation refers to the presence of only single bonds in the compounds. 6. **Conclusion**: Therefore, methane, ethane, and propane form a homologous series because they: - Have the same functional group (alkanes). - Differ by a CH₂ unit. - Follow the same general formula (CₙH₂ₙ₊₂). - Are saturated hydrocarbons. **Final Answer**: Methane, ethane, and propane are said to form a homologous series because all are saturated hydrocarbons that differ from each other by a CH₂ unit.

To answer the question, "Methane, ethane, and propane are said to form a homologous series because all are...", we need to understand the characteristics that define a homologous series in organic chemistry. ### Step-by-Step Solution: 1. **Definition of Homologous Series**: A homologous series is a group of organic compounds that have the same functional group and similar chemical properties, but differ from each other by a specific structural unit. **Hint**: Remember that a homologous series consists of compounds with similar properties but different structures. ...
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MTG IIT JEE FOUNDATION-CARBON AND ITS COMPOUNDS -Exercise (Multiple Choice Questions) (LEVEL - 1)
  1. Alcohols can be prepared by hydration of

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  2. The reaction CH(4)+Cl(2)underset("light")overset("hv")rarrCH(3)Cl+HCl ...

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  3. When ethanoic acid is heated with NaHCO(3) the gas evolved is

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  4. Methane, ethane and propane are said to form a homologous series becau...

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  5. Which of the following belong to the same homologous series?

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  6. Ethane can be prepared by reaction of ethanol with

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  7. Which of the following is the functional group for carboxylic acid?

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  8. The structural formula of ethyl ethanoate is

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  9. Conversion of ethanol to ethanoic acid is a/an

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  10. In the reaction, CH(3)COONa+NaOHrarr the gas obtained is

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  11. Ethanol on complete oxidation gives

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  12. When the stopper of a bottle containing a colourless liquid was remove...

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  13. C(2)H(4) reacts with hydrogen in presence og Ni to give

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  14. Vegetable oils which are liquid at room temperature, can be converted ...

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  15. The following reaction is an example of CH(4)+2O(2)rarrCO(2)+2H(2)O+"h...

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  16. Complete the following reaction :

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  17. IUPAC name of (C(2)H(5))(2)CHCH(2)OH is

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  18. IUPAC name of the compound CH(3)underset(CH(3))underset(|)overset(CH...

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  19. IUPAC name of the compound CH(2)=C(CH(3))(2) is

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  20. In the presence of concentrated sulphuric acid, acetic acid reacts wit...

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