Home
Class 10
MATHS
The sum of three consecutive terms of an...

The sum of three consecutive terms of an A.P. is 21 and the sum of the squares of these terms is 165.Then product of the three terms is

A

210

B

140

C

56

D

280

Text Solution

AI Generated Solution

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ARITHMETIC PROGRESSIONS

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (MATCH THE FOLLOWING )|2 Videos
  • ARITHMETIC PROGRESSIONS

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (ASSERTION & REASON TYPE )|5 Videos
  • ARITHMETIC PROGRESSIONS

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (MULTIPLE CHOICE QUESTION )(LEVEL 1 )|35 Videos
  • AREAS RELATED TO CIRCLES

    MTG IIT JEE FOUNDATION|Exercise OLYMPIAD/HOTS CORNER|30 Videos
  • CIRCLES

    MTG IIT JEE FOUNDATION|Exercise Olympiad/HOTS Corner|30 Videos

Similar Questions

Explore conceptually related problems

The sum of three consecutive terms of an AP is 21 and the sum of the squares of these terms is 165. find these terms.

The sum of three consecutive terms of an AP is 21 and the sum of the squares of these terms is 165. Find these terms.

Knowledge Check

  • If the sum of n terms of an A.P. is an(n - 1), then sum of squares of these n terms is

    A
    `(2a^(2))/(3) n (n - 1) (2n - 1)`
    B
    `(2a^(2))/(3) n(n + 1) (2n + 1)`
    C
    `(a^(2))/(6) n (n - 1) (2n - 1)`
    D
    `(a^(2))/(6) n (n + 1) (2n + 1)`
  • If the sum of n terms of an A.P. is an(n - 1) where a ne 0 , then sum of squares of these terms is

    A
    `a^(2)n^(2) (n + 1)^(2)`
    B
    `(2)/(3) a^(2) n (n + 1) (2n + 1)`
    C
    `(2)/(3) a^(2) n (n - 1) (2n - 1)`
    D
    none
  • If the sum of n terms of an A.P is cn (n-1)where c ne 0 then the sum of the squares of these terms is

    A
    `c^2n(n+1)^2`
    B
    `2/3c^2n(n-1)(2n-1)`
    C
    `(2c^2)/(3)n(n+1)(2n+1)`
    D
    none of these
  • Similar Questions

    Explore conceptually related problems

    The sum of three consecutive terms of an A.P. is 9 and the sum of their squares is 35. Find the terms.

    The sum of three consecutive terms of an A.P. is 15 and sum of their squares is 83. Find the terms.

    The sum of three consecutive terms of an A.P. is 30 and their product is 360. Find the terms.

    The sum of four consecutive terms of an A.P. Is 2. The sum of the 3rd and 4th terms is 11. Find the terms.

    If the sum of three consecutive terms of an increasing A.P. is 51 and the product of the first and third of these terms is 273, then the third term is (a) 13 (b) 9 (c) 21 (d) 17