Home
Class 9
PHYSICS
A person is running along a circular tra...

A person is running along a circular track of area ` 625 pi m ^(2) ( pi = 22 // 7)` (= 22/7) with a constant speed. Find the displacement in 15 seconds if he has to complete the race in 30 seconds.

A

200 m

B

100 m

C

25 m

D

50 m

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to determine the displacement of a person running along a circular track after 15 seconds, given that the area of the track is \(625 \pi \, m^2\) and the total time to complete the race is 30 seconds. ### Step 1: Calculate the radius of the circular track The area \(A\) of a circle is given by the formula: \[ A = \pi R^2 \] Given that the area is \(625 \pi \, m^2\), we can set up the equation: \[ \pi R^2 = 625 \pi \] Dividing both sides by \(\pi\): \[ R^2 = 625 \] Taking the square root of both sides: \[ R = \sqrt{625} = 25 \, m \] ### Step 2: Determine the total distance of the circular track The circumference \(C\) of a circle is given by: \[ C = 2 \pi R \] Substituting the value of \(R\): \[ C = 2 \pi (25) = 50 \pi \, m \] Using \(\pi = \frac{22}{7}\): \[ C = 50 \times \frac{22}{7} = \frac{1100}{7} \, m \approx 157.14 \, m \] ### Step 3: Calculate the distance traveled in 15 seconds Since the person completes the race in 30 seconds, in 15 seconds (which is half of 30 seconds), the distance traveled will be half of the total circumference: \[ \text{Distance in 15 seconds} = \frac{1}{2} C = \frac{1}{2} (50 \pi) = 25 \pi \, m \] ### Step 4: Determine the displacement after 15 seconds After 15 seconds, the person will have traveled half the circumference of the circle, which means they will be at the opposite side of the starting point. The displacement is the straight-line distance between the starting point (point A) and the point directly opposite (point B) on the circle. The displacement is equal to the diameter of the circle: \[ \text{Diameter} = 2R = 2 \times 25 = 50 \, m \] ### Final Answer Thus, the displacement of the person after 15 seconds is: \[ \text{Displacement} = 50 \, m \] ---

To solve the problem step by step, we need to determine the displacement of a person running along a circular track after 15 seconds, given that the area of the track is \(625 \pi \, m^2\) and the total time to complete the race is 30 seconds. ### Step 1: Calculate the radius of the circular track The area \(A\) of a circle is given by the formula: \[ A = \pi R^2 \] Given that the area is \(625 \pi \, m^2\), we can set up the equation: ...
Promotional Banner

Topper's Solved these Questions

  • FOOTSTEPS TOWARDS CBSE BOARD

    MTG IIT JEE FOUNDATION|Exercise Section - D |14 Videos
  • FORCE AND LAWS OF MOTION

    MTG IIT JEE FOUNDATION|Exercise OLYMPIAD /HOTS CORNER |20 Videos

Similar Questions

Explore conceptually related problems

Centripetal acceleration of a cyclist completing 7 rounds in a minute along a circular track of radius 5 m with a constant speed ,is

A person X is running around a circular track completing one round every 40 seconds. Another person Y running in the opposite direction meets X every 15 second. The time, expressed in seconds, taken by Y to complete one round is

A person covers half a round on a circular track of radius 20m with constant speed v in pi sec then which of the following is/are correct. (a)Displacement covered is zero (b)Magnitude of change in velocity of a person is 2v (c)The average speed of a person is 20m/sec (d)The average acceleration of a person is equal to zero

A man starts running with constant speed along a circular path of radius sqrt2m He completes two rounds in 16 seconds. The magnitude of the average velocity in first 2 seconds is

Find the area of the shaded region (use pi = (22)/(7) )

MTG IIT JEE FOUNDATION-FOOTSTEPS TOWARDS NEET-Multiple Choice Question
  1. Calculate the mass of a body whose volume is 2m^3 and relative density...

    Text Solution

    |

  2. A block is raised from position A to B by taking two different paths a...

    Text Solution

    |

  3. If wavelength of a wave is 100 m, then 100 waves will cover distanc

    Text Solution

    |

  4. A person is running along a circular track of area 625 pi m ^(2) ( pi...

    Text Solution

    |

  5. A mass of 100 g strikes the wall with speed 5 m//s at an angle as show...

    Text Solution

    |

  6. According to Newton's law of gravitation, every object attracts every ...

    Text Solution

    |

  7. A boy is rotating in a circular motion, a stone of mass 500 g by using...

    Text Solution

    |

  8. A simple pendulum performs 18 oscillations per second. The mechanical ...

    Text Solution

    |

  9. v20

    Text Solution

    |

  10. The velocity-time graph of a ball moving on the surface of a floor as ...

    Text Solution

    |

  11. A force of 100 N displacement an object through 0.2 m and does work of...

    Text Solution

    |

  12. Which of the following is not matched correctly

    Text Solution

    |

  13. Which of the following statement(s) is/are true about sound waves? (...

    Text Solution

    |

  14. The mass of a body of a body is increased 4 fold and mass of other bod...

    Text Solution

    |

  15. Two boys A and B lift 100 bricks through the same height in 5 minutes ...

    Text Solution

    |

  16. A car and a lorry are moving with same momentum, if same braking force...

    Text Solution

    |

  17. The distance of a particle as a function of time is shown here. The gr...

    Text Solution

    |

  18. A sound wave has a frequency 1000 Hz and wavelength 34 cm. How long wi...

    Text Solution

    |

  19. Moon is the natural satellite of the earth and weight of an object on ...

    Text Solution

    |

  20. A man has mass 70 kg and the mass of his wife is 50 kg. The ratio of t...

    Text Solution

    |