Home
Class 12
PHYSICS
Derive a expression for the electric pot...

Derive a expression for the electric potential at any point due to electric dipole. Rewrite this expression if point of observation lies on: (1) axial line of dipole (ii) equatorial line of dipole.

Text Solution

Verified by Experts

Let P = be any point at a distance r from O.
`r_(1)=AP`
`r_(2)=BP`
`theta=` be the angle between OP and dipole moment `vecp` .
Consider an electric dipole AB having charge (-q) at point A and charge (+q) at point B. Let O be the centre to the dipole.
The electric potential at P due to -q charge is given by
`V_(1)=1/(4 pi varepsilon_(0))((-q))/r_(1)`
`V_(1)=1/(4 pi varepsilon_(0))(q)/r_(1)" "...(1)`
`:." "`Potential at P due to + charge is given by
`V_(1)=1/(4 pi varepsilon_(0))q/r_(2)" "...(2)`
Using principle of superposition,
`V=V_(1)+V_(2)`
`:." "V=(-1)/(4 pi varepsilon_(0))q/r_(1)+1/(4 pi varepsilon_(0))`
`:." "V=q/(4 pi varepsilon_(0))[1/r^(2)-1/r_(1)]" "...(3)`
Draw a perpendicular from A which meets the line OP at C when produced such that `AP~~PC`. Also draw the BD perpendicular on OP such that `BP~~PD`.
Now, In `Delta OAC`.
`cos theta=(OC)/(OA)`
`costheta=(OC)/a`
`OC=a cos theta`
In `Delta OBD," "cos theta=(OD)/(OB)`
`cos theta=(OD)/a implies OD = a cos theta`
Then `r_(1)=OP+OC=r+a cos theta`
`r_(2)=OP-OD=r-a cos theta`
Substituting the values in equation (3)
`:." "V=q/(4 pi varepsilon_(0))[1/((r-a cos theta))-1/((r+a cos theta))]`
`V=q/(4 pi varepsilon_(0))[(r+a cos theta-(r-a cos theta))/(r^(2)-a^(2)cos^(2)theta)]`
`V=q/(4 pi varepsilon_(0))[(r+a cos theta-r+a cos theta)/(r^(2)-a^(2)cos^(2)theta)]`
`V=q/(4 pi varepsilon_(0))[(2a cos theta)/(r^(2)-a^(2) cos^(2)theta)]`
Since, `(q xx 2a=p)`
`V=(q xx 2 a cos theta)/(4 pi varepsilon_(0)[r^(2)-a^(2)cos^(2)theta])`
`:." "V=(p cos theta)/(4 pi varepsilon_(0)(r^(2)-a^(2)cos^(2)theta))`
when r>>>>a, then `a^(2)` can be neglected in comparison to `r^(2)`.
`:." "V = (p cos theta)/(4 pi varepsilon_(0)r^(2))`
(i) When point P lies on the axial line
then`" "thrta=0^(@)`
`:." "V=(p cos0^(@))/(4 pi varepsilon_(0)r^(2))`
`V=p/(4 pi varepsilon_(0)r^(2))`
`i.e.," "V prop 1/r^(2)`
(2) If point P lies on the equatorial line of dipole
then`" "theta = 90^@`
`V = (p cos 90^@)/4 pi varepsilon_(0)r^(2))`
`V=0" "[:. cos 90^(@)=0]`
`:." "`Electric potential due to dipole is zero on all points on equatorial line.
Promotional Banner

Similar Questions

Explore conceptually related problems

Derive an expression for electric potential at general point of an electric dipole.

Derive an expression for electric potential at a point due to a point charge.

Derive an expression for electric potential at a point due to electric dipole. Hence find its value on equatorial line?

Derive an expression for the electric potential at a point along the axial line of an electric dipole.

Derive an expression for electric potential at any point due to electric dipole. Show that the potential at a point on the equatorial line of an electric dipole is zero.