Can we say that if a perfect square is of `n` digits, then its square root will have `n/2` digits if `n` is even or ` ((n+1)/2)` if n is odd ?

The value of (-1)^(n)=-1 if n is odd

One place of perfect square number cannot have the digit

If a square matrix A is involutory, then A^(2n+1) is equal to:

Prove that sqrtn , n being not a perfect square, is not a rational number.

If the sum of n natural numbers is one sixth of their squares, then n is :

Number of ways in which three numbers in A.P. can be selected from 1,2,3,..., n is a. ((n-1)/2)^2 if n is even b. ((n-2)/4)^ if n is even c. ((n-1)/4)^2 if n is odd d. none of these

Find the 18th and 25th terms of the sequence defined by : t_n= {(n(n+2),if n is even natural number),((4n)/(n^2+1), if n is odd natural number):} .

If A is a skew symmetric matrix, then show that A^n is symmetric if n is even and A^n is skew symmetric if n is odd, n in N .

The number of non-squares numbers lying between the square of 2 consecutive numbers n and (n+1) are