Home
Class 12
CHEMISTRY
""^(60 m)Co rarr ^(60)Co emits gamma- ra...

`""^(60 m)Co rarr ^(60)`Co emits `gamma`- radiations of wavelength `3 xx 10^(-10)`m. Assuming each nuclei emits one wavelength, with what mass per mole of two nuclei differ ?

A

`4.43 xx 10^(-9)` g

B

`4.43 xx 10^(-6)`g

C

`4.43 xx 10^(-3)` g

D

4.43 g

Text Solution

Verified by Experts

The correct Answer is:
B
E/photon ` = (N.hc)/(lambda)` Also, `E = mc^(2) " "therefore " " (N.hc)/(lambda) = mc^(2)`
`therefore m = (N.h)/(c.lambda) = (6.02 xx 10^(23) xx 6.626 xx 10^(-34))/(3 xx 10^(8) xx 3 xx 10^(-10)) = 4.43 xx 10^(-9)` kg `= 4.43 xx 10^(-6)` g
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • NUCLEAR CHEMISTRY

    BRILLIANT PUBLICATION|Exercise LEVEL-III (Single Correct Answer Type ) |8 Videos

  • NUCLEAR CHEMISTRY

    BRILLIANT PUBLICATION|Exercise LEVEL-III (Multiple Correct Answer Type) |10 Videos

  • NUCLEAR CHEMISTRY

    BRILLIANT PUBLICATION|Exercise LEVEL-I|45 Videos

  • NITROGEN COMPOUNDS

    BRILLIANT PUBLICATION|Exercise LEVEL-III (Linked Comprehension Type)|9 Videos

  • P-BLOCK ELEMENTS

    BRILLIANT PUBLICATION|Exercise LEVEL-III|50 Videos

Similar Questions

Explore conceptually related problems

Two coherent sources of wavelength 6.2 xx 10^(-7)m produce interference. The path difference corresponding to tenth order maximum, will be

A radiation has a frequency of '6 xx 10^(14)' cycles per second (or 'Hz' ). Calculate the wavelength of the radiation in nanometers '(ln m=10^(-9)m)'

Knowledge Check

  • The minimum intensity of light to be detected by human eye is 10^(-10)W//m^2 . The number of photons of wavelength 5.6 xx 10^(-7) m entering the eye, with pupil area 10^6 m^2 , per second for vision will be nearly

    A
    100
    B
    200
    C
    300
    D
    400

  • The minimum intensity of light to be detected by human eye is 10^(-10)W//m^(2). The number of photons of wavelength 5.6 xx 10^(-7)m entering the eye, with pupil area 10ʻm, per second for vision will be nearly

    A
    100
    B
    200
    C
    300
    D
    400

  • A 600 W mercury lamp emits monochromatic radiation of wavelength 331.3 nm. How many photons are emitted from the lamp per second ? ( h = 6.626 xx 10^(-34) Js, velocity of light = 3 xx 10^(8) ms^(-1) )

    A
    `1 xx 10^(19)`
    B
    `1 xx 10^(20)`
    C
    `1 xx 10^(21)`
    D
    `1 xx 10^(23)`

    • Similar Questions

    Explore conceptually related problems

    Nitrogen laser produces a radiation at a wavelength of 337.1 nm. If the number of photons emitted is 5.6 xx 10^(24) per second, calculate the power of this laser.

    Two coherent sources of wavelength 6.2 xx 10^(-7)m produce interference. The path difference corresponding to tenth order maximum, will be

    In a gas, two waves of wavelengths 1 m and 1.01 m are superposed and produce 10 beats in 3 s. The velocity of sound in the medium is :

    A radio transmitter radiated 1 kW power at a wavelength 198.6 m. How many photons does it emit per second?

    A nucleus at rest undergoes a decay emitting an alpha -particle of de Broglie wavelength lamda=5.76xx 10^(-15) m. The mass of the daughter nucleus D = 223.610 amu and the mass of an a-particle = 4.002 amu. Take 1 amu = 1.656 xx10^(-27) kg and Plack's constant h=6.63 xx10^(-34) Js. The total kinetic energy of the two particles is of the order of

    Home
    Profile