For the reaction :` N _(2) + 3H_(2) to 2 NH _(3)` The rate of reaction measured as `(Delta [ NH _(3) ] )/( Delta t )` we found to be ` 2 xx 10 ^(-4) mol L ^(-1) sec ^(-1).` Calculate the rate of reaction expressed in terms of `N _(2).`

Explanation

`N _(2) + 3 H _(2) to 2 NH _(3)`
The rate of reaction is `2 .4xx 10 ^(-4)`
`r = ( - d [ N _(2) ] )/( dt ) = (-1)/( 3) (d [ H_(2) ] )/( dt ) =(1)/(2) (d)/(dt) [ NH _(3) ]`
Rate of reaction at a particular time remains same in tarms of all reactants or products.